adapt to change: lu() now gives partial piv LU, here we want fullPivLu()

1 files changed, 1 insertions, 1 deletions

diff --git a/doc/snippets/Tutorial_solve_multiple_rhs.cpp b/doc/snippets/Tutorial_solve_multiple_rhs.cpp
index 72dab9075..5411a44ab 100644
--- a/doc/snippets/Tutorial_solve_multiple_rhs.cpp
+++ b/doc/snippets/Tutorial_solve_multiple_rhs.cpp
@@ -3,7 +3,7 @@ A << 1,2,3,  4,5,6,  7,8,10;
 Matrix<float,3,2> B;
 B << 3,1, 3,1, 4,1;
 Matrix<float,3,2> X;
-X = A.lu().solve(B);
+X = A.fullPivLu().solve(B);
 cout << "The solution with right-hand side (3,3,4) is:" << endl;
 cout << X.col(0) << endl;
 cout << "The solution with right-hand side (1,1,1) is:" << endl;