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-rw-r--r--theories/Numbers/Natural/Abstract/NAdd.v109
1 files changed, 17 insertions, 92 deletions
diff --git a/theories/Numbers/Natural/Abstract/NAdd.v b/theories/Numbers/Natural/Abstract/NAdd.v
index 91ae5b70..9f0b54a6 100644
--- a/theories/Numbers/Natural/Abstract/NAdd.v
+++ b/theories/Numbers/Natural/Abstract/NAdd.v
@@ -8,74 +8,30 @@
(* Evgeny Makarov, INRIA, 2007 *)
(************************************************************************)
-(*i $Id: NAdd.v 11674 2008-12-12 19:48:40Z letouzey $ i*)
+(*i $Id$ i*)
Require Export NBase.
-Module NAddPropFunct (Import NAxiomsMod : NAxiomsSig).
-Module Export NBasePropMod := NBasePropFunct NAxiomsMod.
+Module NAddPropFunct (Import N : NAxiomsSig').
+Include NBasePropFunct N.
-Open Local Scope NatScope.
+(** For theorems about [add] that are both valid for [N] and [Z], see [NZAdd] *)
+(** Now comes theorems valid for natural numbers but not for Z *)
-Theorem add_wd :
- forall n1 n2 : N, n1 == n2 -> forall m1 m2 : N, m1 == m2 -> n1 + m1 == n2 + m2.
-Proof NZadd_wd.
-
-Theorem add_0_l : forall n : N, 0 + n == n.
-Proof NZadd_0_l.
-
-Theorem add_succ_l : forall n m : N, (S n) + m == S (n + m).
-Proof NZadd_succ_l.
-
-(** Theorems that are valid for both natural numbers and integers *)
-
-Theorem add_0_r : forall n : N, n + 0 == n.
-Proof NZadd_0_r.
-
-Theorem add_succ_r : forall n m : N, n + S m == S (n + m).
-Proof NZadd_succ_r.
-
-Theorem add_comm : forall n m : N, n + m == m + n.
-Proof NZadd_comm.
-
-Theorem add_assoc : forall n m p : N, n + (m + p) == (n + m) + p.
-Proof NZadd_assoc.
-
-Theorem add_shuffle1 : forall n m p q : N, (n + m) + (p + q) == (n + p) + (m + q).
-Proof NZadd_shuffle1.
-
-Theorem add_shuffle2 : forall n m p q : N, (n + m) + (p + q) == (n + q) + (m + p).
-Proof NZadd_shuffle2.
-
-Theorem add_1_l : forall n : N, 1 + n == S n.
-Proof NZadd_1_l.
-
-Theorem add_1_r : forall n : N, n + 1 == S n.
-Proof NZadd_1_r.
-
-Theorem add_cancel_l : forall n m p : N, p + n == p + m <-> n == m.
-Proof NZadd_cancel_l.
-
-Theorem add_cancel_r : forall n m p : N, n + p == m + p <-> n == m.
-Proof NZadd_cancel_r.
-
-(* Theorems that are valid for natural numbers but cannot be proved for Z *)
-
-Theorem eq_add_0 : forall n m : N, n + m == 0 <-> n == 0 /\ m == 0.
+Theorem eq_add_0 : forall n m, n + m == 0 <-> n == 0 /\ m == 0.
Proof.
intros n m; induct n.
-(* The next command does not work with the axiom add_0_l from NAddSig *)
-rewrite add_0_l. intuition reflexivity.
-intros n IH. rewrite add_succ_l.
-setoid_replace (S (n + m) == 0) with False using relation iff by
+nzsimpl; intuition.
+intros n IH. nzsimpl.
+setoid_replace (S (n + m) == 0) with False by
(apply -> neg_false; apply neq_succ_0).
-setoid_replace (S n == 0) with False using relation iff by
+setoid_replace (S n == 0) with False by
(apply -> neg_false; apply neq_succ_0). tauto.
Qed.
Theorem eq_add_succ :
- forall n m : N, (exists p : N, n + m == S p) <->
- (exists n' : N, n == S n') \/ (exists m' : N, m == S m').
+ forall n m, (exists p, n + m == S p) <->
+ (exists n', n == S n') \/ (exists m', m == S m').
Proof.
intros n m; cases n.
split; intro H.
@@ -88,11 +44,11 @@ left; now exists n.
exists (n + m); now rewrite add_succ_l.
Qed.
-Theorem eq_add_1 : forall n m : N,
+Theorem eq_add_1 : forall n m,
n + m == 1 -> n == 1 /\ m == 0 \/ n == 0 /\ m == 1.
Proof.
intros n m H.
-assert (H1 : exists p : N, n + m == S p) by now exists 0.
+assert (H1 : exists p, n + m == S p) by now exists 0.
apply -> eq_add_succ in H1. destruct H1 as [[n' H1] | [m' H1]].
left. rewrite H1 in H; rewrite add_succ_l in H; apply succ_inj in H.
apply -> eq_add_0 in H. destruct H as [H2 H3]; rewrite H2 in H1; now split.
@@ -100,7 +56,7 @@ right. rewrite H1 in H; rewrite add_succ_r in H; apply succ_inj in H.
apply -> eq_add_0 in H. destruct H as [H2 H3]; rewrite H3 in H1; now split.
Qed.
-Theorem succ_add_discr : forall n m : N, m ~= S (n + m).
+Theorem succ_add_discr : forall n m, m ~= S (n + m).
Proof.
intro n; induct m.
apply neq_sym. apply neq_succ_0.
@@ -108,49 +64,18 @@ intros m IH H. apply succ_inj in H. rewrite add_succ_r in H.
unfold not in IH; now apply IH.
Qed.
-Theorem add_pred_l : forall n m : N, n ~= 0 -> P n + m == P (n + m).
+Theorem add_pred_l : forall n m, n ~= 0 -> P n + m == P (n + m).
Proof.
intros n m; cases n.
intro H; now elim H.
intros n IH; rewrite add_succ_l; now do 2 rewrite pred_succ.
Qed.
-Theorem add_pred_r : forall n m : N, m ~= 0 -> n + P m == P (n + m).
+Theorem add_pred_r : forall n m, m ~= 0 -> n + P m == P (n + m).
Proof.
intros n m H; rewrite (add_comm n (P m));
rewrite (add_comm n m); now apply add_pred_l.
Qed.
-(* One could define n <= m as exists p : N, p + n == m. Then we have
-dichotomy:
-
-forall n m : N, n <= m \/ m <= n,
-
-i.e.,
-
-forall n m : N, (exists p : N, p + n == m) \/ (exists p : N, p + m == n) (1)
-
-We will need (1) in the proof of induction principle for integers
-constructed as pairs of natural numbers. The formula (1) can be proved
-using properties of order and truncated subtraction. Thus, p would be
-m - n or n - m and (1) would hold by theorem sub_add from Sub.v
-depending on whether n <= m or m <= n. However, in proving induction
-for integers constructed from natural numbers we do not need to
-require implementations of order and sub; it is enough to prove (1)
-here. *)
-
-Theorem add_dichotomy :
- forall n m : N, (exists p : N, p + n == m) \/ (exists p : N, p + m == n).
-Proof.
-intros n m; induct n.
-left; exists m; apply add_0_r.
-intros n IH.
-destruct IH as [[p H] | [p H]].
-destruct (zero_or_succ p) as [H1 | [p' H1]]; rewrite H1 in H.
-rewrite add_0_l in H. right; exists (S 0); rewrite H; rewrite add_succ_l; now rewrite add_0_l.
-left; exists p'; rewrite add_succ_r; now rewrite add_succ_l in H.
-right; exists (S p). rewrite add_succ_l; now rewrite H.
-Qed.
-
End NAddPropFunct.