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authorGravatar Stephane Glondu <steph@glondu.net>2009-02-19 13:13:14 +0100
committerGravatar Stephane Glondu <steph@glondu.net>2009-02-19 13:13:14 +0100
commita0a94c1340a63cdb824507b973393882666ba52a (patch)
tree73aa4eb32cbd176379bc91b21c184e2a6882bfe3 /test-suite
parentcfbfe13f5b515ae2e3c6cdd97e2ccee03bc26e56 (diff)
Imported Upstream version 8.2-1+dfsgupstream/8.2-1+dfsg
Diffstat (limited to 'test-suite')
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+(* Test parsing/interpretation/pretyping on a large example *)
+(* Expected time < 0.10s *)
+
+(* Complexity of unification used to be exponential in the number of nested
+ constants, as pointed out by Georges Gonthier and Nicolas Tabareau (a.o.)
+
+ The problem is that unification of id^n+1(0) and id^n+1(1) proceeds as:
+ - try not unfold the outermost id by trying to unify its arguments:
+ 1st rec. call on id^n(0) id^n(1), which fails
+ - Coq then tries to unfold id^n+1(k) which produces id^n(k)
+ - 2nd rec. call on id^n(0) id^n(1), which also fails
+ Complexity is thus at least exponential.
+
+ This is fixed (in the ground case), by the fact that when we try to
+ unify two ground terms (ie. without unsolved evars), we call kernel
+ conversion and if this fails, then the terms are not unifiable.
+ Hopefully, kernel conversion is not exponential on cases like the one
+ below thanks to sharing (as long as unfolding the fonction does not
+ use its argument under a binder).
+
+ There are probably still many cases where unification goes astray.
+ *)
+
+
+Definition id (n:nat) := n.
+Goal
+ (id (id (id (id
+ (id (id (id (id
+ (id (id (id (id
+ (id (id (id (id
+ (id (id (id (id
+ 0
+ ))))
+ ))))
+ ))))
+ ))))
+ ))))
+ =
+ (id (id (id (id
+ (id (id (id (id
+ (id (id (id (id
+ (id (id (id (id
+ (id (id (id (id
+ 1
+ ))))
+ ))))
+ ))))
+ ))))
+ ))))
+.
+Time try refine (refl_equal _).