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-// Copyright 2005, Google Inc.
-// All rights reserved.
-//
-// Redistribution and use in source and binary forms, with or without
-// modification, are permitted provided that the following conditions are
-// met:
-//
-//     * Redistributions of source code must retain the above copyright
-// notice, this list of conditions and the following disclaimer.
-//     * Redistributions in binary form must reproduce the above
-// copyright notice, this list of conditions and the following disclaimer
-// in the documentation and/or other materials provided with the
-// distribution.
-//     * Neither the name of Google Inc. nor the names of its
-// contributors may be used to endorse or promote products derived from
-// this software without specific prior written permission.
-//
-// THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
-// "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT
-// LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR
-// A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT
-// OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
-// SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT
-// LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
-// DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
-// THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
-// (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE
-// OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
-
-// A sample program demonstrating using Google C++ testing framework.
-//
-// Author: wan@google.com (Zhanyong Wan)
-
-#include "sample1.h"
-
-// Returns n! (the factorial of n).  For negative n, n! is defined to be 1.
-int Factorial(int n) {
-  int result = 1;
-  for (int i = 1; i <= n; i++) {
-    result *= i;
-  }
-
-  return result;
-}
-
-// Returns true iff n is a prime number.
-bool IsPrime(int n) {
-  // Trivial case 1: small numbers
-  if (n <= 1) return false;
-
-  // Trivial case 2: even numbers
-  if (n % 2 == 0) return n == 2;
-
-  // Now, we have that n is odd and n >= 3.
-
-  // Try to divide n by every odd number i, starting from 3
-  for (int i = 3; ; i += 2) {
-    // We only have to try i up to the square root of n
-    if (i > n/i) break;
-
-    // Now, we have i <= n/i < n.
-    // If n is divisible by i, n is not prime.
-    if (n % i == 0) return false;
-  }
-
-  // n has no integer factor in the range (1, n), and thus is prime.
-  return true;
-}