(************************************************************************) (* v * The Coq Proof Assistant / The Coq Development Team *) (* Prop := | le_n : n <= n | le_S : forall m:nat, n <= m -> n <= S m where "n <= m" := (le n m) : nat_scope. >> *) Open Local Scope nat_scope. Implicit Types m n p : nat. (** * [le] is a pre-order *) (** Reflexivity *) Theorem le_refl : forall n, n <= n. Proof. exact le_n. Qed. (** Transitivity *) Theorem le_trans : forall n m p, n <= m -> m <= p -> n <= p. Proof. induction 2; auto. Qed. Hint Resolve le_trans: arith v62. (** * Properties of [le] w.r.t. successor, predecessor and 0 *) (** Comparison to 0 *) Theorem le_0_n : forall n, 0 <= n. Proof. induction n; auto. Qed. Theorem le_Sn_0 : forall n, ~ S n <= 0. Proof. red in |- *; intros n H. change (IsSucc 0) in |- *; elim H; simpl in |- *; auto with arith. Qed. Hint Resolve le_0_n le_Sn_0: arith v62. Theorem le_n_0_eq : forall n, n <= 0 -> 0 = n. Proof. induction n; auto with arith. intro; contradiction le_Sn_0 with n. Qed. Hint Immediate le_n_0_eq: arith v62. (** [le] and successor *) Theorem le_n_S : forall n m, n <= m -> S n <= S m. Proof. induction 1; auto. Qed. Theorem le_n_Sn : forall n, n <= S n. Proof. auto. Qed. Hint Resolve le_n_S le_n_Sn : arith v62. Theorem le_Sn_le : forall n m, S n <= m -> n <= m. Proof. intros n m H; apply le_trans with (S n); auto with arith. Qed. Hint Immediate le_Sn_le: arith v62. Theorem le_S_n : forall n m, S n <= S m -> n <= m. Proof. intros n m H; change (pred (S n) <= pred (S m)) in |- *. destruct H; simpl; auto with arith. Qed. Hint Immediate le_S_n: arith v62. Theorem le_Sn_n : forall n, ~ S n <= n. Proof. induction n; auto with arith. Qed. Hint Resolve le_Sn_n: arith v62. (** [le] and predecessor *) Theorem le_pred_n : forall n, pred n <= n. Proof. induction n; auto with arith. Qed. Hint Resolve le_pred_n: arith v62. Theorem le_pred : forall n m, n <= m -> pred n <= pred m. Proof. destruct n; simpl; auto with arith. destruct m; simpl; auto with arith. Qed. (** * [le] is a order on [nat] *) (** Antisymmetry *) Theorem le_antisym : forall n m, n <= m -> m <= n -> n = m. Proof. intros n m H; destruct H as [|m' H]; auto with arith. intros H1. absurd (S m' <= m'); auto with arith. apply le_trans with n; auto with arith. Qed. Hint Immediate le_antisym: arith v62. (** * A different elimination principle for the order on natural numbers *) Lemma le_elim_rel : forall P:nat -> nat -> Prop, (forall p, P 0 p) -> (forall p (q:nat), p <= q -> P p q -> P (S p) (S q)) -> forall n m, n <= m -> P n m. Proof. induction n; auto with arith. intros m Le. elim Le; auto with arith. Qed. (* begin hide *) Notation le_O_n := le_0_n (only parsing). Notation le_Sn_O := le_Sn_0 (only parsing). Notation le_n_O_eq := le_n_0_eq (only parsing). (* end hide *)