(************************************************************************) (* v * The Coq Proof Assistant / The Coq Development Team *) (* m <= p -> n <= p. Proof. induction 2; auto. Qed. Hint Resolve le_trans: arith v62. (** Order, successor and predecessor *) Theorem le_n_S : forall n m, n <= m -> S n <= S m. Proof. induction 1; auto. Qed. Theorem le_n_Sn : forall n, n <= S n. Proof. auto. Qed. Theorem le_O_n : forall n, 0 <= n. Proof. induction n; auto. Qed. Hint Resolve le_n_S le_n_Sn le_O_n le_n_S: arith v62. Theorem le_pred_n : forall n, pred n <= n. Proof. induction n; auto with arith. Qed. Hint Resolve le_pred_n: arith v62. Theorem le_Sn_le : forall n m, S n <= m -> n <= m. Proof. intros n m H; apply le_trans with (S n); auto with arith. Qed. Hint Immediate le_Sn_le: arith v62. Theorem le_S_n : forall n m, S n <= S m -> n <= m. Proof. intros n m H; change (pred (S n) <= pred (S m)) in |- *. destruct H; simpl; auto with arith. Qed. Hint Immediate le_S_n: arith v62. Theorem le_pred : forall n m, n <= m -> pred n <= pred m. Proof. destruct n; simpl; auto with arith. destruct m; simpl; auto with arith. Qed. (** Comparison to 0 *) Theorem le_Sn_O : forall n, ~ S n <= 0. Proof. red in |- *; intros n H. change (IsSucc 0) in |- *; elim H; simpl in |- *; auto with arith. Qed. Hint Resolve le_Sn_O: arith v62. Theorem le_n_O_eq : forall n, n <= 0 -> 0 = n. Proof. induction n; auto with arith. intro; contradiction le_Sn_O with n. Qed. Hint Immediate le_n_O_eq: arith v62. (** Negative properties *) Theorem le_Sn_n : forall n, ~ S n <= n. Proof. induction n; auto with arith. Qed. Hint Resolve le_Sn_n: arith v62. (** Antisymmetry *) Theorem le_antisym : forall n m, n <= m -> m <= n -> n = m. Proof. intros n m h; destruct h as [| m0 H]; auto with arith. intros H1. absurd (S m0 <= m0); auto with arith. apply le_trans with n; auto with arith. Qed. Hint Immediate le_antisym: arith v62. (** A different elimination principle for the order on natural numbers *) Lemma le_elim_rel : forall P:nat -> nat -> Prop, (forall p, P 0 p) -> (forall p (q:nat), p <= q -> P p q -> P (S p) (S q)) -> forall n m, n <= m -> P n m. Proof. induction n; auto with arith. intros m Le. elim Le; auto with arith. Qed.