(* An example with constr subentries *) Module A. Declare Custom Entry myconstr. Notation "[ x ]" := x (x custom myconstr at level 6). Notation "x + y" := (Nat.add x y) (in custom myconstr at level 5). Notation "x * y" := (Nat.mul x y) (in custom myconstr at level 4). Notation "< x >" := x (in custom myconstr at level 3, x constr at level 10). Check [ < 0 > + < 1 > * < 2 >]. Axiom a : nat. Notation b := a. Check [ < b > + < a > * < 2 >]. Declare Custom Entry anotherconstr. Notation "[ x ]" := x (x custom myconstr at level 6). Notation "<< x >>" := x (in custom myconstr at level 3, x custom anotherconstr at level 10). Notation "# x" := (Some x) (in custom anotherconstr at level 8, x constr at level 9). Check [ << # 0 >> ]. End A. Module B. Inductive Expr := | Mul : Expr -> Expr -> Expr | Add : Expr -> Expr -> Expr | One : Expr. Declare Custom Entry expr. Notation "[ expr ]" := expr (expr custom expr at level 2). Notation "1" := One (in custom expr at level 0). Notation "x y" := (Mul x y) (in custom expr at level 1, left associativity). Notation "x + y" := (Add x y) (in custom expr at level 2, left associativity). Notation "( x )" := x (in custom expr at level 0, x at level 2). Notation "{ x }" := x (in custom expr at level 0, x constr). Notation "x" := x (in custom expr at level 0, x ident). Axiom f : nat -> Expr. Check [1 {f 1}]. Check fun x y z => [1 + y z + {f x}]. Check fun e => match e with | [x y + z] => [x + y z] | [1 + 1] => [1] | y => [y + e] end. End B. Module C. Inductive Expr := | Add : Expr -> Expr -> Expr | One : Expr. Declare Custom Entry expr. Notation "[ expr ]" := expr (expr custom expr at level 1). Notation "1" := One (in custom expr at level 0). Notation "x + y" := (Add x y) (in custom expr at level 2, left associativity). Notation "( x )" := x (in custom expr at level 0, x at level 2). (* Check the use of a two-steps coercion from constr to expr 1 then from expr 0 to expr 2 (note that camlp5 parsing is more tolerant and does not require parentheses to parse from level 2 while at level 1) *) Check [1 + 1]. End C.