(* BZ#932 *) (* Expected time < 1.00s *) (* Let n be the number of let-in. The complexity comes from the fact that each implicit arguments of f was in a larger and larger context. To compute the type of "let _ := f ?Tn 0 in f ?T 0", "f ?Tn 0" is substituted in the type of "f ?T 0" which is ?T. This type is an evar instantiated on the n variables denoting the "f ?Ti 0". One obtain "?T[1;...;n-1;f ?Tn[1;...;n-1] 0]". To compute the type of "let _ := f ?Tn-1 0 in let _ := f ?Tn 0 in f ?T 0", another substitution is done leading to "?T[1;...;n-2;f ?Tn[1;...;n-2] 0;f ?Tn[1;...;n-2;f ?Tn[1;...;n-2] 0] 0]" and so on. At the end, we get a term of exponential size *) (* A way to cut the complexity could have been to remove the dependency in anonymous variables in evars but this breaks intuitive behaviour (see Case15.v); another approach could be to substitute lazily and/or to simultaneously substitute let binders and evars *) Variable P : Set -> Set. Variable f : forall A : Set, A -> P A. Time Check let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in let _ := f _ 0 in f _ 0.