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(***********************************************************************)
(* v * The Coq Proof Assistant / The Coq Development Team *)
(* <O___,, * INRIA-Rocquencourt & LRI-CNRS-Orsay *)
(* \VV/ *************************************************************)
(* // * This file is distributed under the terms of the *)
(* * GNU Lesser General Public License Version 2.1 *)
(***********************************************************************)
(*i $Id$ i*)
Require Arith.
(** maximum of two natural numbers *)
Fixpoint max [n:nat] : nat -> nat :=
[m:nat]Cases n m of
O _ => m
| (S n') O => n
| (S n') (S m') => (S (max n' m'))
end.
(** Simplifications of [max] *)
Lemma max_SS : (n,m:nat)((S (max n m))=(max (S n) (S m))).
Proof.
Auto with arith.
Qed.
Lemma max_sym : (n,m:nat)(max n m)=(max m n).
Proof.
NewInduction n;NewInduction m;Simpl;Auto with arith.
Qed.
(** [max] and [le] *)
Lemma max_l : (n,m:nat)(le m n)->(max n m)=n.
Proof.
NewInduction n;NewInduction m;Simpl;Auto with arith.
Qed.
Lemma max_r : (n,m:nat)(le n m)->(max n m)=m.
Proof.
NewInduction n;NewInduction m;Simpl;Auto with arith.
Qed.
Lemma le_max_l : (n,m:nat)(le n (max n m)).
Proof.
NewInduction n; Intros; Simpl; Auto with arith.
Elim m; Intros; Simpl; Auto with arith.
Qed.
Lemma le_max_r : (n,m:nat)(le m (max n m)).
Proof.
NewInduction n; Simpl; Auto with arith.
NewInduction m; Simpl; Auto with arith.
Qed.
Hints Resolve max_r max_l le_max_l le_max_r: arith v62.
(** [max n m] is equal to [n] or [m] *)
Lemma max_dec : (n,m:nat){(max n m)=n}+{(max n m)=m}.
Proof.
NewInduction n;NewInduction m;Simpl;Auto with arith.
Elim (IHn m);Intro H;Elim H;Auto.
Qed.
Lemma max_case : (n,m:nat)(P:nat->Set)(P n)->(P m)->(P (max n m)).
Proof.
NewInduction n; Simpl; Auto with arith.
NewInduction m; Intros; Simpl; Auto with arith.
Pattern (max n m); Apply IHn ; Auto with arith.
Qed.
Lemma max_case2 : (n,m:nat)(P:nat->Prop)(P n)->(P m)->(P (max n m)).
Proof.
NewInduction n; Simpl; Auto with arith.
NewInduction m; Intros; Simpl; Auto with arith.
Pattern (max n m); Apply IHn ; Auto with arith.
Qed.
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