(* $Id$ *) Require Lt. Require Plus. Require Compare_dec. Require Even. (* Here we define n/2 and prove some of its properties *) Fixpoint div2 [n:nat] : nat := Cases n of O => O | (S O) => O | (S (S n')) => (S (div2 n')) end. (* Since div2 is recursively defined on 0, 1 and (S (S n)), it is * useful to prove the corresponding induction principle *) Lemma ind_0_1_SS : (P:nat->Prop) (P O) -> (P (S O)) -> ((n:nat)(P n)->(P (S (S n)))) -> (n:nat)(P n). Proof. Intros. Cut (n:nat)(P n)/\(P (S n)). Intros. Elim (H2 n). Auto with arith. Induction n0. Auto with arith. Intros. Elim H2; Auto with arith. Qed. (* 0 n/2 < n *) Lemma lt_div2 : (n:nat) (lt O n) -> (lt (div2 n) n). Proof. Intro n. Pattern n. Apply ind_0_1_SS. Intro. Inversion H. Auto with arith. Intros. Simpl. Case (zerop n0). Intro. Rewrite e. Auto with arith. Auto with arith. Qed. Hints Resolve lt_div2 : arith. (* Properties related to the parity *) Lemma even_odd_div2 : (n:nat) ((even n)<->(div2 n)=(div2 (S n))) /\ ((odd n)<->(S (div2 n))=(div2 (S n))). Proof. Intro n. Pattern n. Apply ind_0_1_SS. (* n = 0 *) Split. Split; Auto with arith. Split. Intro H. Inversion H. Intro H. Absurd (S (div2 O))=(div2 (S O)); Auto with arith. (* n = 1 *) Split. Split. Intro. Inversion H. Inversion H1. Intro H. Absurd (div2 (S O))=(div2 (S (S O))). Simpl. Discriminate. Assumption. Split; Auto with arith. (* n = (S (S n')) *) Intros. Decompose [and] H. Unfold iff in H0 H1. Decompose [and] H0. Decompose [and] H1. Clear H H0 H1. Split; Split; Auto with arith. Intro H. Inversion H. Inversion H1. Change (S (div2 n0))=(S (div2 (S n0))). Auto with arith. Intro H. Inversion H. Inversion H1. Change (S (S (div2 n0)))=(S (div2 (S n0))). Auto with arith. Qed. (* Specializations *) Lemma even_div2 : (n:nat) (even n) -> (div2 n)=(div2 (S n)). Proof [n:nat](proj1 ? ? (proj1 ? ? (even_odd_div2 n))). Lemma div2_even : (n:nat) (div2 n)=(div2 (S n)) -> (even n). Proof [n:nat](proj2 ? ? (proj1 ? ? (even_odd_div2 n))). Lemma odd_div2 : (n:nat) (odd n) -> (S (div2 n))=(div2 (S n)). Proof [n:nat](proj1 ? ? (proj2 ? ? (even_odd_div2 n))). Lemma div2_odd : (n:nat) (S (div2 n))=(div2 (S n)) -> (odd n). Proof [n:nat](proj2 ? ? (proj2 ? ? (even_odd_div2 n))). Hints Resolve even_div2 div2_even odd_div2 div2_odd : arith. (* Properties related to the double (2n) *) Definition double := [n:nat](plus n n). Hints Unfold double : arith. Lemma double_S : (n:nat) (double (S n))=(S (S (double n))). Proof. Intro. Unfold double. Simpl. Auto with arith. Qed. Hints Resolve double_S : arith. Lemma even_odd_double : (n:nat) ((even n)<->n=(double (div2 n))) /\ ((odd n)<->n=(S (double (div2 n)))). Proof. Intro n. Pattern n. Apply ind_0_1_SS. (* n = 0 *) Split; Split; Auto with arith. Intro H. Inversion H. (* n = 1 *) Split; Split; Auto with arith. Intro H. Inversion H. Inversion H1. (* n = (S (S n')) *) Intros. Decompose [and] H. Unfold iff in H0 H1. Decompose [and] H0. Decompose [and] H1. Clear H H0 H1. Split; Split. Intro H. Inversion H. Inversion H1. Simpl. Rewrite <- plus_n_Sm. Auto with arith. Simpl. Rewrite <- plus_n_Sm. Intro H. Injection H. Auto with arith. Intro H. Inversion H. Inversion H1. Simpl. Rewrite <- plus_n_Sm. Auto with arith. Simpl. Rewrite <- plus_n_Sm. Intro H. Injection H. Auto with arith. Qed. (* Specializations *) Lemma even_double : (n:nat) (even n) -> n=(double (div2 n)). Proof [n:nat](proj1 ? ? (proj1 ? ? (even_odd_double n))). Lemma double_even : (n:nat) n=(double (div2 n)) -> (even n). Proof [n:nat](proj2 ? ? (proj1 ? ? (even_odd_double n))). Lemma odd_double : (n:nat) (odd n) -> n=(S (double (div2 n))). Proof [n:nat](proj1 ? ? (proj2 ? ? (even_odd_double n))). Lemma double_odd : (n:nat) n=(S (double (div2 n))) -> (odd n). Proof [n:nat](proj2 ? ? (proj2 ? ? (even_odd_double n))). Hints Resolve even_double double_even odd_double double_odd : arith. (* Application: * if n is even then there is a p such that n = 2p * if n is odd then there is a p such that n = 2p+1 * * (Immediate: it is n/2) *) Lemma even_2n : (n:nat) (even n) -> { p:nat | n=(double p) }. Proof. Intros n H. Exists (div2 n). Auto with arith. Qed. Lemma odd_S2n : (n:nat) (odd n) -> { p:nat | n=(S (double p)) }. Proof. Intros n H. Exists (div2 n). Auto with arith. Qed.