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-rwxr-xr-xdoc/RefMan-syn.tex6
1 files changed, 3 insertions, 3 deletions
diff --git a/doc/RefMan-syn.tex b/doc/RefMan-syn.tex
index bf8375d3e..b367f0e9e 100755
--- a/doc/RefMan-syn.tex
+++ b/doc/RefMan-syn.tex
@@ -178,7 +178,7 @@ to be done. Here is an example.
\begin{coq_example*}
Notation "'EX' x | p" := (ex ? [x]p) (at level 10).
-Notation "'EX' x | p & q" := (ex2 t [x]p [x]q) (at level 10).
+Notation "'EX' x | p & q" := (ex2 ? [x]p [x]q) (at level 10).
\end{coq_example*}
In order to factorise the left part of the rules, the subexpression
@@ -191,7 +191,7 @@ as follows.
\begin{coq_example*}
Notation "'EX' x | p" := (ex ? [x]p) (at level 10, p at level 9).
-Notation "'EX' x | p & q" := (ex2 t [x]p [x]q)
+Notation "'EX' x | p & q" := (ex2 ? [x]p [x]q)
(at level 10, p at level 9).
\end{coq_example*}
@@ -200,7 +200,7 @@ to put q at the same level as p, hence the final version of the rules
\begin{coq_example*}
Notation "'EX' x | p" := (ex ? [x]p) (at level 10, p at level 9).
-Notation "'EX' x | p & q" := (ex2 t [x]p [x]q)
+Notation "'EX' x | p & q" := (ex2 ? [x]p [x]q)
(at level 10, p, q at level 9).
\end{coq_example*}