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authorGravatar Matej Kosik <m4tej.kosik@gmail.com>2015-11-09 16:43:47 +0100
committerGravatar Hugo Herbelin <Hugo.Herbelin@inria.fr>2015-12-10 09:35:19 +0100
commit15311e51c20e6edc3b97f12d483dd15bfbc1164c (patch)
treea8b723557f6ac0e4196e48825a43c046f5a3f707 /doc
parent67d0db55d55dd2c650a33f11794e8a6747fc518b (diff)
PROPOSITION: Example was simplified
Diffstat (limited to 'doc')
-rw-r--r--doc/refman/RefMan-cic.tex35
1 files changed, 8 insertions, 27 deletions
diff --git a/doc/refman/RefMan-cic.tex b/doc/refman/RefMan-cic.tex
index 2f4016d71..ac860b827 100644
--- a/doc/refman/RefMan-cic.tex
+++ b/doc/refman/RefMan-cic.tex
@@ -1688,33 +1688,14 @@ when $a_{k_i}$ starts with a constructor.
This last restriction is needed in order to keep strong normalization
and corresponds to the reduction for primitive recursive operators.
-We can illustrate this behavior on examples.
-\begin{coq_example}
-Goal forall n m:nat, plus (S n) m = S (plus n m).
-reflexivity.
-Abort.
-Goal forall f:forest, sizet (node f) = S (sizef f).
-reflexivity.
-Abort.
-\end{coq_example}
-But assuming the definition of a son function from \tree\ to \forest:
-\begin{coq_example}
-Definition sont (t:tree) : forest
- := let (f) := t in f.
-\end{coq_example}
-The following is not a conversion but can be proved after a case analysis.
-% (******************************************************************)
-% (** Error: Impossible to unify .... **)
-\begin{coq_example}
-Goal forall t:tree, sizet t = S (sizef (sont t)).
-Fail reflexivity.
-destruct t.
-reflexivity.
-\end{coq_example}
-\begin{coq_eval}
-Abort.
-\end{coq_eval}
-% QUESTION: What are we trying to say with the above examples?
+The following reductions are now possible:
+\def\plus{\mathsf{plus}}
+\def\tri{\triangleright_\iota}
+\begin{eqnarray*}
+ \plus~(\nS~(\nS~\nO))~(\nS~\nO) & \tri & \nS~(\plus~(\nS~\nO)~(\nS~\nO))\\
+ & \tri & \nS~(\nS~(\plus~\nO~(\nS~\nO)))\\
+ & \tri & \nS~(\nS~(\nS~\nO))\\
+\end{eqnarray*}
% La disparition de Program devrait rendre la construction Match obsolete
% \subsubsection{The {\tt Match \ldots with \ldots end} expression}