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authorGravatar Matej Kosik <m4tej.kosik@gmail.com>2015-11-05 15:25:50 +0100
committerGravatar Hugo Herbelin <Hugo.Herbelin@inria.fr>2015-12-10 09:35:15 +0100
commitd95fd157ac6600f4784de44ef558c4880aed624b (patch)
tree7d6cc3a7eed8270fe0cb88aa47b2599809d6885f
parent5d32732cdf110e44a51cf6a23a8972f015e3fc88 (diff)
COMMENT: question
-rw-r--r--doc/refman/RefMan-cic.tex5
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diff --git a/doc/refman/RefMan-cic.tex b/doc/refman/RefMan-cic.tex
index 9e5f18f52..f69b40278 100644
--- a/doc/refman/RefMan-cic.tex
+++ b/doc/refman/RefMan-cic.tex
@@ -1246,6 +1246,11 @@ same as proving:
$(\haslengthA~(\Nil~A)~\nO)$ and $\forall a:A, \forall l:\ListA,
(\haslengthA~l~(\length~l)) \ra
(\haslengthA~(\cons~A~a~l)~(\nS~(\length~l)))$.
+% QUESTION: Wouldn't something like:
+%
+% http://matej-kosik.github.io/www/doc/coq/notes/25__has_length.html
+%
+% be more comprehensible?
One conceptually simple way to do that, following the basic scheme
proposed by Martin-L\"of in his Intuitionistic Type Theory, is to